Consider this snippet from a file:
It’s a list of integers (the full file has 122 of them), but the delimiter is three newline characters. I needed to get rid of the empty lines in this file.
I thought of it as replacing three
\n characters with one, so it seemed like a good place to use the
However, according to this FAQ for
sed, it’s impossible to use
\n in a
sed command to strip out newlines.
5.10. Why can’t I match or delete a newline using the \n escape sequence? Why can’t I match 2 or more lines using \n?
The \n will never match the newline at the end-of-line because the newline is always stripped off before the line is placed into the pattern space. To get 2 or more lines into the pattern space, use the ‘N’ command or something similar (such as ‘H;…;g;’).
Sed works like this: sed reads one line at a time, chops off the terminating newline, puts what is left into the pattern space where the sed script can address or change it, and when the pattern space is printed, appends a newline to stdout (or to a file). If the pattern space is entirely or partially deleted with ‘d’ or ‘D’, the newline is not added in such cases. Thus, scripts like
sed 's/\n//' file # to delete newlines from each line
sed 's/\n/foo\n/' file # to add a word to the end of each line
will never work, because the trailing newline is removed before the line is put into the pattern space. To perform the above tasks, use one of these scripts instead:
tr -d '\n' < file # use tr to delete newlines
sed ':a;N;$!ba;s/\n//g' file # GNU sed to delete newlines
sed 's/$/ foo/' file # add "foo" to end of each line
Basically, the utility reads the input line-by-line, so it never sees the newlines anyway. It looks like we can’t replace multiple newlines with a single newline after all.
However, a regex trick I found was to detect empty lines and delete them:
sed /^$/d FILE
This regex looks for any line that ends immediately after it begins, then deletes that line. It worked perfectly for my needs.